Solve each system: System 1
(y=2x−1, y=−x+5): set the right sides equal,
2x−1=−x+5 →
3x=6 →
x=2. Substitute
x=2: y=2(2)−1=3, so the solution is
(2,3). System 2
(y=x+1, y=−x+7): set the right sides equal,
x+1=−x+7 →
2x=6 →
x=3. Substitute
x=3: y=3+1=4, so the solution is
(3,4). System 3
(y=2x, y=−x+9): set the right sides equal,
2x=−x+9 →
3x=9 →
x=3. Substitute
x=3: y=2(3)=6, so the solution is
(3,6).